2(3+3)=3(2p+2)

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Solution for 2(3+3)=3(2p+2) equation: 



2(3+3)=3(2p+2)

We move all terms to the left:

2(3+3)-(3(2p+2))=0

We add all the numbers together, and all the variables

-(3(2p+2))+26=0



We calculate terms in parentheses: -(3(2p+2)), so:

3(2p+2)

We multiply parentheses

6p+6

Back to the equation:

-(6p+6)



We get rid of parentheses

-6p-6+26=0

We add all the numbers together, and all the variables

-6p+20=0

We move all terms containing p to the left, all other terms to the right

-6p=-20

p=-20/-6

p=3+1/3

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