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2(3+2k)=4(7k-2)-2/5
We move all terms to the left:
2(3+2k)-(4(7k-2)-2/5)=0
We add all the numbers together, and all the variables
2(2k+3)-(4(7k-2)-2/5)=0
We multiply parentheses
4k-(4(7k-2)-2/5)+6=0
We multiply all the terms by the denominator
4k*5)-(4(7k-2)-2+6*5)=0
We add all the numbers together, and all the variables
4k*5)-(4(7k-2)=0
Wy multiply elements
20k^2=0
a = 20; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·20·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$k=\frac{-b}{2a}=\frac{0}{40}=0$
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