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2(3(x+5)-9)=-3(2x-4)
We move all terms to the left:
2(3(x+5)-9)-(-3(2x-4))=0
We calculate terms in parentheses: -(-3(2x-4)), so:We get rid of parentheses
-3(2x-4)
We multiply parentheses
-6x+12
Back to the equation:
-(-6x+12)
2(3(x+5)-9)+6x-12=0
We add all the numbers together, and all the variables
6x+2(3(x+5)-9)-12=0
We move all terms containing x to the left, all other terms to the right
6x+2(3(x+5)-9)=12
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