2(2z-29)=3(2z-29)

Solution for 2(2z-29)=3(2z-29) equation:

Simplifying
2(2z + -29) = 3(2z + -29)

Reorder the terms:
2(-29 + 2z) = 3(2z + -29)
(-29 * 2 + 2z * 2) = 3(2z + -29)
(-58 + 4z) = 3(2z + -29)

Reorder the terms:
-58 + 4z = 3(-29 + 2z)
-58 + 4z = (-29 * 3 + 2z * 3)
-58 + 4z = (-87 + 6z)

Solving
-58 + 4z = -87 + 6z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-6z' to each side of the equation.
-58 + 4z + -6z = -87 + 6z + -6z

Combine like terms: 4z + -6z = -2z
-58 + -2z = -87 + 6z + -6z

Combine like terms: 6z + -6z = 0
-58 + -2z = -87 + 0
-58 + -2z = -87

Add '58' to each side of the equation.
-58 + 58 + -2z = -87 + 58

Combine like terms: -58 + 58 = 0
0 + -2z = -87 + 58
-2z = -87 + 58

Combine like terms: -87 + 58 = -29
-2z = -29

Divide each side by '-2'.
z = 14.5

Simplifying
z = 14.5