2(2z+2)=4(2z+6)

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Solution for 2(2z+2)=4(2z+6) equation: 



2(2z+2)=4(2z+6)

We move all terms to the left:

2(2z+2)-(4(2z+6))=0

We multiply parentheses

4z-(4(2z+6))+4=0



We calculate terms in parentheses: -(4(2z+6)), so:

4(2z+6)

We multiply parentheses

8z+24

Back to the equation:

-(8z+24)



We get rid of parentheses

4z-8z-24+4=0

We add all the numbers together, and all the variables

-4z-20=0

We move all terms containing z to the left, all other terms to the right

-4z=20

z=20/-4

z=-5

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