2(2y-6)-y=32

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Solution for 2(2y-6)-y=32 equation: 



2(2y-6)-y=32

We move all terms to the left:

2(2y-6)-y-(32)=0

We add all the numbers together, and all the variables

-1y+2(2y-6)-32=0

We multiply parentheses

-1y+4y-12-32=0

We add all the numbers together, and all the variables

3y-44=0

We move all terms containing y to the left, all other terms to the right

3y=44

y=44/3

y=14+2/3

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