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2(2y-5)=(y-6)
We move all terms to the left:
2(2y-5)-((y-6))=0
We multiply parentheses
4y-((y-6))-10=0
We calculate terms in parentheses: -((y-6)), so:We get rid of parentheses
(y-6)
We get rid of parentheses
y-6
Back to the equation:
-(y-6)
4y-y+6-10=0
We add all the numbers together, and all the variables
3y-4=0
We move all terms containing y to the left, all other terms to the right
3y=4
y=4/3
y=1+1/3
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