2(2y-3)=3(y+4)

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Solution for 2(2y-3)=3(y+4) equation: 



2(2y-3)=3(y+4)

We move all terms to the left:

2(2y-3)-(3(y+4))=0

We multiply parentheses

4y-(3(y+4))-6=0



We calculate terms in parentheses: -(3(y+4)), so:

3(y+4)

We multiply parentheses

3y+12

Back to the equation:

-(3y+12)



We get rid of parentheses

4y-3y-12-6=0

We add all the numbers together, and all the variables

y-18=0

We move all terms containing y to the left, all other terms to the right

y=18

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