2(2y-2)=4(-2y+8)

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Solution for 2(2y-2)=4(-2y+8) equation: 



2(2y-2)=4(-2y+8)

We move all terms to the left:

2(2y-2)-(4(-2y+8))=0

We multiply parentheses

4y-(4(-2y+8))-4=0



We calculate terms in parentheses: -(4(-2y+8)), so:

4(-2y+8)

We multiply parentheses

-8y+32

Back to the equation:

-(-8y+32)



We get rid of parentheses

4y+8y-32-4=0

We add all the numbers together, and all the variables

12y-36=0

We move all terms containing y to the left, all other terms to the right

12y=36

y=36/12

y=3

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