2(2y-1)+y4/9(y+3)=g

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Solution for 2(2y-1)+y4/9(y+3)=g equation: 


x in (-oo:+oo)

2*(2*y-1)+((y^4)/9)*(y+3) = g // - g

2*(2*y-1)+((y^4)/9)*(y+3)-g = 0

2*(2*y-1)+1/9*y^4*(y+3)-g = 0

2*(2*y-1)+1/9*y^4*(y+3)-g = 0

1/9*y^5-g+1/3*y^4+4*y-2 = 0

1/9*y^5-g+1/3*y^4+4*y-2 = 0

x belongs to the empty set

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