2(2y+7)=3(2y-4)

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Solution for 2(2y+7)=3(2y-4) equation: 



2(2y+7)=3(2y-4)

We move all terms to the left:

2(2y+7)-(3(2y-4))=0

We multiply parentheses

4y-(3(2y-4))+14=0



We calculate terms in parentheses: -(3(2y-4)), so:

3(2y-4)

We multiply parentheses

6y-12

Back to the equation:

-(6y-12)



We get rid of parentheses

4y-6y+12+14=0

We add all the numbers together, and all the variables

-2y+26=0

We move all terms containing y to the left, all other terms to the right

-2y=-26

y=-26/-2

y=+13

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