2(2y+4)-y=2(8y-8)

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Solution for 2(2y+4)-y=2(8y-8) equation: 



2(2y+4)-y=2(8y-8)

We move all terms to the left:

2(2y+4)-y-(2(8y-8))=0

We add all the numbers together, and all the variables

-1y+2(2y+4)-(2(8y-8))=0

We multiply parentheses

-1y+4y-(2(8y-8))+8=0



We calculate terms in parentheses: -(2(8y-8)), so:

2(8y-8)

We multiply parentheses

16y-16

Back to the equation:

-(16y-16)



We add all the numbers together, and all the variables

3y-(16y-16)+8=0

We get rid of parentheses

3y-16y+16+8=0

We add all the numbers together, and all the variables

-13y+24=0

We move all terms containing y to the left, all other terms to the right

-13y=-24

y=-24/-13

y=1+11/13

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