2(2y+3)=2(3-2y)+8y

Solution for 2(2y+3)=2(3-2y)+8y equation:

2(2y+3)=2(3-2y)+8y

We move all terms to the left:

2(2y+3)-(2(3-2y)+8y)=0

We add all the numbers together, and all the variables

2(2y+3)-(2(-2y+3)+8y)=0

We multiply parentheses

4y-(2(-2y+3)+8y)+6=0


We calculate terms in parentheses: -(2(-2y+3)+8y), so:

2(-2y+3)+8y

We add all the numbers together, and all the variables

8y+2(-2y+3)

We multiply parentheses

8y-4y+6

We add all the numbers together, and all the variables

4y+6

Back to the equation:

-(4y+6)


We get rid of parentheses

4y-4y-6+6=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0