2(2x/3+x)=40

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Solution for 2(2x/3+x)=40 equation: 



2(2x/3+x)=40

We move all terms to the left:

2(2x/3+x)-(40)=0



Domain of the equation: 3+x)!=0

We move all terms containing x to the left, all other terms to the right

x)!=-3

x!=-3/1

x!=-3

x∈R



We add all the numbers together, and all the variables

2(+x+2x/3)-40=0

We multiply parentheses

2x+4x-40=0

We add all the numbers together, and all the variables

6x-40=0

We move all terms containing x to the left, all other terms to the right

6x=40

x=40/6

x=6+2/3

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