2(2x-7)-3=2(x-4)+7

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Solution for 2(2x-7)-3=2(x-4)+7 equation: 



2(2x-7)-3=2(x-4)+7

We move all terms to the left:

2(2x-7)-3-(2(x-4)+7)=0

We multiply parentheses

4x-(2(x-4)+7)-14-3=0



We calculate terms in parentheses: -(2(x-4)+7), so:

2(x-4)+7

We multiply parentheses

2x-8+7

We add all the numbers together, and all the variables

2x-1

Back to the equation:

-(2x-1)



We add all the numbers together, and all the variables

4x-(2x-1)-17=0

We get rid of parentheses

4x-2x+1-17=0

We add all the numbers together, and all the variables

2x-16=0

We move all terms containing x to the left, all other terms to the right

2x=16

x=16/2

x=8

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