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2(2x-5)=5-3(3x+1)
We move all terms to the left:
2(2x-5)-(5-3(3x+1))=0
We multiply parentheses
4x-(5-3(3x+1))-10=0
We calculate terms in parentheses: -(5-3(3x+1)), so:We get rid of parentheses
5-3(3x+1)
determiningTheFunctionDomain -3(3x+1)+5
We multiply parentheses
-9x-3+5
We add all the numbers together, and all the variables
-9x+2
Back to the equation:
-(-9x+2)
4x+9x-2-10=0
We add all the numbers together, and all the variables
13x-12=0
We move all terms containing x to the left, all other terms to the right
13x=12
x=12/13
x=12/13
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