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2(2x-5)=2(3x-5)-2x
We move all terms to the left:
2(2x-5)-(2(3x-5)-2x)=0
We multiply parentheses
4x-(2(3x-5)-2x)-10=0
We calculate terms in parentheses: -(2(3x-5)-2x), so:We get rid of parentheses
2(3x-5)-2x
We add all the numbers together, and all the variables
-2x+2(3x-5)
We multiply parentheses
-2x+6x-10
We add all the numbers together, and all the variables
4x-10
Back to the equation:
-(4x-10)
4x-4x+10-10=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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