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2(2x-5)(2x+5)=((4x-10)(4x+10)
We move all terms to the left:
2(2x-5)(2x+5)-(((4x-10)(4x+10))=0
We use the square of the difference formula
4x^2+16x^2-25+100=0
We add all the numbers together, and all the variables
20x^2+75=0
a = 20; b = 0; c = +75;
Δ = b2-4ac
Δ = 02-4·20·75
Δ = -6000
Delta is less than zero, so there is no solution for the equation
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