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2(2x-4)=3(2x+2)
We move all terms to the left:
2(2x-4)-(3(2x+2))=0
We multiply parentheses
4x-(3(2x+2))-8=0
We calculate terms in parentheses: -(3(2x+2)), so:We get rid of parentheses
3(2x+2)
We multiply parentheses
6x+6
Back to the equation:
-(6x+6)
4x-6x-6-8=0
We add all the numbers together, and all the variables
-2x-14=0
We move all terms containing x to the left, all other terms to the right
-2x=14
x=14/-2
x=-7
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