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2(2x-4)=16-4(3+x)
We move all terms to the left:
2(2x-4)-(16-4(3+x))=0
We add all the numbers together, and all the variables
2(2x-4)-(16-4(x+3))=0
We multiply parentheses
4x-(16-4(x+3))-8=0
We calculate terms in parentheses: -(16-4(x+3)), so:We get rid of parentheses
16-4(x+3)
determiningTheFunctionDomain -4(x+3)+16
We multiply parentheses
-4x-12+16
We add all the numbers together, and all the variables
-4x+4
Back to the equation:
-(-4x+4)
4x+4x-4-8=0
We add all the numbers together, and all the variables
8x-12=0
We move all terms containing x to the left, all other terms to the right
8x=12
x=12/8
x=1+1/2
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