2(2x-4)+6=6(x-2)

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Solution for 2(2x-4)+6=6(x-2) equation: 



2(2x-4)+6=6(x-2)

We move all terms to the left:

2(2x-4)+6-(6(x-2))=0

We multiply parentheses

4x-(6(x-2))-8+6=0



We calculate terms in parentheses: -(6(x-2)), so:

6(x-2)

We multiply parentheses

6x-12

Back to the equation:

-(6x-12)



We add all the numbers together, and all the variables

4x-(6x-12)-2=0

We get rid of parentheses

4x-6x+12-2=0

We add all the numbers together, and all the variables

-2x+10=0

We move all terms containing x to the left, all other terms to the right

-2x=-10

x=-10/-2

x=+5

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