2(2x-3)=3(x-4)+1

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Solution for 2(2x-3)=3(x-4)+1 equation: 



2(2x-3)=3(x-4)+1

We move all terms to the left:

2(2x-3)-(3(x-4)+1)=0

We multiply parentheses

4x-(3(x-4)+1)-6=0



We calculate terms in parentheses: -(3(x-4)+1), so:

3(x-4)+1

We multiply parentheses

3x-12+1

We add all the numbers together, and all the variables

3x-11

Back to the equation:

-(3x-11)



We get rid of parentheses

4x-3x+11-6=0

We add all the numbers together, and all the variables

x+5=0

We move all terms containing x to the left, all other terms to the right

x=-5

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