2(2x-3)-8(x-1)+1=0

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Solution for 2(2x-3)-8(x-1)+1=0 equation:


Simplifying
2(2x + -3) + -8(x + -1) + 1 = 0

Reorder the terms:
2(-3 + 2x) + -8(x + -1) + 1 = 0
(-3 * 2 + 2x * 2) + -8(x + -1) + 1 = 0
(-6 + 4x) + -8(x + -1) + 1 = 0

Reorder the terms:
-6 + 4x + -8(-1 + x) + 1 = 0
-6 + 4x + (-1 * -8 + x * -8) + 1 = 0
-6 + 4x + (8 + -8x) + 1 = 0

Reorder the terms:
-6 + 8 + 1 + 4x + -8x = 0

Combine like terms: -6 + 8 = 2
2 + 1 + 4x + -8x = 0

Combine like terms: 2 + 1 = 3
3 + 4x + -8x = 0

Combine like terms: 4x + -8x = -4x
3 + -4x = 0

Solving
3 + -4x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -4x = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -4x = 0 + -3
-4x = 0 + -3

Combine like terms: 0 + -3 = -3
-4x = -3

Divide each side by '-4'.
x = 0.75

Simplifying
x = 0.75

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