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2(2x-3)+6(x-4)=-2(3x-1)
We move all terms to the left:
2(2x-3)+6(x-4)-(-2(3x-1))=0
We multiply parentheses
4x+6x-(-2(3x-1))-6-24=0
We calculate terms in parentheses: -(-2(3x-1)), so:We add all the numbers together, and all the variables
-2(3x-1)
We multiply parentheses
-6x+2
Back to the equation:
-(-6x+2)
10x-(-6x+2)-30=0
We get rid of parentheses
10x+6x-2-30=0
We add all the numbers together, and all the variables
16x-32=0
We move all terms containing x to the left, all other terms to the right
16x=32
x=32/16
x=2
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