2(2x-1)-4=3(4x-3)+19

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Solution for 2(2x-1)-4=3(4x-3)+19 equation: 



2(2x-1)-4=3(4x-3)+19

We move all terms to the left:

2(2x-1)-4-(3(4x-3)+19)=0

We multiply parentheses

4x-(3(4x-3)+19)-2-4=0



We calculate terms in parentheses: -(3(4x-3)+19), so:

3(4x-3)+19

We multiply parentheses

12x-9+19

We add all the numbers together, and all the variables

12x+10

Back to the equation:

-(12x+10)



We add all the numbers together, and all the variables

4x-(12x+10)-6=0

We get rid of parentheses

4x-12x-10-6=0

We add all the numbers together, and all the variables

-8x-16=0

We move all terms containing x to the left, all other terms to the right

-8x=16

x=16/-8

x=-2

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