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2(2x+x-3)=3(x+5)
We move all terms to the left:
2(2x+x-3)-(3(x+5))=0
We add all the numbers together, and all the variables
2(3x-3)-(3(x+5))=0
We multiply parentheses
6x-(3(x+5))-6=0
We calculate terms in parentheses: -(3(x+5)), so:We get rid of parentheses
3(x+5)
We multiply parentheses
3x+15
Back to the equation:
-(3x+15)
6x-3x-15-6=0
We add all the numbers together, and all the variables
3x-21=0
We move all terms containing x to the left, all other terms to the right
3x=21
x=21/3
x=7
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