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2(2x+6)=x(x+3)
We move all terms to the left:
2(2x+6)-(x(x+3))=0
We multiply parentheses
4x-(x(x+3))+12=0
We calculate terms in parentheses: -(x(x+3)), so:We get rid of parentheses
x(x+3)
We multiply parentheses
x^2+3x
Back to the equation:
-(x^2+3x)
-x^2+4x-3x+12=0
We add all the numbers together, and all the variables
-1x^2+x+12=0
a = -1; b = 1; c = +12;
Δ = b2-4ac
Δ = 12-4·(-1)·12
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-7}{2*-1}=\frac{-8}{-2} =+4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+7}{2*-1}=\frac{6}{-2} =-3 $
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