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2(2x+2)+3x=2(x+1)+10
We move all terms to the left:
2(2x+2)+3x-(2(x+1)+10)=0
We add all the numbers together, and all the variables
3x+2(2x+2)-(2(x+1)+10)=0
We multiply parentheses
3x+4x-(2(x+1)+10)+4=0
We calculate terms in parentheses: -(2(x+1)+10), so:We add all the numbers together, and all the variables
2(x+1)+10
We multiply parentheses
2x+2+10
We add all the numbers together, and all the variables
2x+12
Back to the equation:
-(2x+12)
7x-(2x+12)+4=0
We get rid of parentheses
7x-2x-12+4=0
We add all the numbers together, and all the variables
5x-8=0
We move all terms containing x to the left, all other terms to the right
5x=8
x=8/5
x=1+3/5
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