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2(2x+1)-3(1-2x)=5(x-2)
We move all terms to the left:
2(2x+1)-3(1-2x)-(5(x-2))=0
We add all the numbers together, and all the variables
2(2x+1)-3(-2x+1)-(5(x-2))=0
We multiply parentheses
4x+6x-(5(x-2))+2-3=0
We calculate terms in parentheses: -(5(x-2)), so:We add all the numbers together, and all the variables
5(x-2)
We multiply parentheses
5x-10
Back to the equation:
-(5x-10)
10x-(5x-10)-1=0
We get rid of parentheses
10x-5x+10-1=0
We add all the numbers together, and all the variables
5x+9=0
We move all terms containing x to the left, all other terms to the right
5x=-9
x=-9/5
x=-1+4/5
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