2(2w+1)=4(w+2)-5

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Solution for 2(2w+1)=4(w+2)-5 equation: 



2(2w+1)=4(w+2)-5

We move all terms to the left:

2(2w+1)-(4(w+2)-5)=0

We multiply parentheses

4w-(4(w+2)-5)+2=0



We calculate terms in parentheses: -(4(w+2)-5), so:

4(w+2)-5

We multiply parentheses

4w+8-5

We add all the numbers together, and all the variables

4w+3

Back to the equation:

-(4w+3)



We get rid of parentheses

4w-4w-3+2=0

We add all the numbers together, and all the variables

-1!=0

There is no solution for this equation

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