2(2t+4)=28

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Solution for 2(2t+4)=28 equation: 



2(2t+4)=28

We move all terms to the left:

2(2t+4)-(28)=0

We multiply parentheses

4t+8-28=0

We add all the numbers together, and all the variables

4t-20=0

We move all terms containing t to the left, all other terms to the right

4t=20

t=20/4

t=5

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