2(2t+4)=2(8+t)

Solution for 2(2t+4)=2(8+t) equation:

2(2t+4)=2(8+t)

We move all terms to the left:

2(2t+4)-(2(8+t))=0

We add all the numbers together, and all the variables

2(2t+4)-(2(t+8))=0

We multiply parentheses

4t-(2(t+8))+8=0


We calculate terms in parentheses: -(2(t+8)), so:

2(t+8)

We multiply parentheses

2t+16

Back to the equation:

-(2t+16)


We get rid of parentheses

4t-2t-16+8=0

We add all the numbers together, and all the variables

2t-8=0

We move all terms containing t to the left, all other terms to the right

2t=8

t=8/2

t=4