2(2t+3)=6(t-2)

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Solution for 2(2t+3)=6(t-2) equation: 



2(2t+3)=6(t-2)

We move all terms to the left:

2(2t+3)-(6(t-2))=0

We multiply parentheses

4t-(6(t-2))+6=0



We calculate terms in parentheses: -(6(t-2)), so:

6(t-2)

We multiply parentheses

6t-12

Back to the equation:

-(6t-12)



We get rid of parentheses

4t-6t+12+6=0

We add all the numbers together, and all the variables

-2t+18=0

We move all terms containing t to the left, all other terms to the right

-2t=-18

t=-18/-2

t=+9

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