2(2t+1)-13=t-(t+10)

Solution for 2(2t+1)-13=t-(t+10) equation:

Simplifying
2(2t + 1) + -13 = t + -1(t + 10)

Reorder the terms:
2(1 + 2t) + -13 = t + -1(t + 10)
(1 * 2 + 2t * 2) + -13 = t + -1(t + 10)
(2 + 4t) + -13 = t + -1(t + 10)

Reorder the terms:
2 + -13 + 4t = t + -1(t + 10)

Combine like terms: 2 + -13 = -11
-11 + 4t = t + -1(t + 10)

Reorder the terms:
-11 + 4t = t + -1(10 + t)
-11 + 4t = t + (10 * -1 + t * -1)
-11 + 4t = t + (-10 + -1t)

Reorder the terms:
-11 + 4t = -10 + t + -1t

Combine like terms: t + -1t = 0
-11 + 4t = -10 + 0
-11 + 4t = -10

Solving
-11 + 4t = -10

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '11' to each side of the equation.
-11 + 11 + 4t = -10 + 11

Combine like terms: -11 + 11 = 0
0 + 4t = -10 + 11
4t = -10 + 11

Combine like terms: -10 + 11 = 1
4t = 1

Divide each side by '4'.
t = 0.25

Simplifying
t = 0.25