2(2t+1)-11=t-(t+8)

Solution for 2(2t+1)-11=t-(t+8) equation:

2(2t+1)-11=t-(t+8)

We move all terms to the left:

2(2t+1)-11-(t-(t+8))=0

We multiply parentheses

4t-(t-(t+8))+2-11=0


We calculate terms in parentheses: -(t-(t+8)), so:

t-(t+8)

We get rid of parentheses

t-t-8

We add all the numbers together, and all the variables

-8

Back to the equation:

-(-8)


We add all the numbers together, and all the variables

4t-1=0

We move all terms containing t to the left, all other terms to the right

4t=1

t=1/4

t=1/4