2(2n-5)=-(6-3n)+n-4

Solution for 2(2n-5)=-(6-3n)+n-4 equation:

2(2n-5)=-(6-3n)+n-4

We move all terms to the left:

2(2n-5)-(-(6-3n)+n-4)=0

We add all the numbers together, and all the variables

2(2n-5)-(-(-3n+6)+n-4)=0

We multiply parentheses

4n-(-(-3n+6)+n-4)-10=0


We calculate terms in parentheses: -(-(-3n+6)+n-4), so:

-(-3n+6)+n-4

We add all the numbers together, and all the variables

n-(-3n+6)-4

We get rid of parentheses

n+3n-6-4

We add all the numbers together, and all the variables

4n-10

Back to the equation:

-(4n-10)


We get rid of parentheses

4n-4n+10-10=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0