2(2n-4)=2(5-n)

Solution for 2(2n-4)=2(5-n) equation:

2(2n-4)=2(5-n)

We move all terms to the left:

2(2n-4)-(2(5-n))=0

We add all the numbers together, and all the variables

2(2n-4)-(2(-1n+5))=0

We multiply parentheses

4n-(2(-1n+5))-8=0


We calculate terms in parentheses: -(2(-1n+5)), so:

2(-1n+5)

We multiply parentheses

-2n+10

Back to the equation:

-(-2n+10)


We get rid of parentheses

4n+2n-10-8=0

We add all the numbers together, and all the variables

6n-18=0

We move all terms containing n to the left, all other terms to the right

6n=18

n=18/6

n=3