2(2n+4)-(n+2)=-3(n-10)

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Solution for 2(2n+4)-(n+2)=-3(n-10) equation: 



2(2n+4)-(n+2)=-3(n-10)

We move all terms to the left:

2(2n+4)-(n+2)-(-3(n-10))=0

We multiply parentheses

4n-(n+2)-(-3(n-10))+8=0

We get rid of parentheses

4n-n-(-3(n-10))-2+8=0



We calculate terms in parentheses: -(-3(n-10)), so:

-3(n-10)

We multiply parentheses

-3n+30

Back to the equation:

-(-3n+30)



We add all the numbers together, and all the variables

3n-(-3n+30)+6=0

We get rid of parentheses

3n+3n-30+6=0

We add all the numbers together, and all the variables

6n-24=0

We move all terms containing n to the left, all other terms to the right

6n=24

n=24/6

n=4

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