2(2n+1)=7(3n+4)+8

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Solution for 2(2n+1)=7(3n+4)+8 equation: 



2(2n+1)=7(3n+4)+8

We move all terms to the left:

2(2n+1)-(7(3n+4)+8)=0

We multiply parentheses

4n-(7(3n+4)+8)+2=0



We calculate terms in parentheses: -(7(3n+4)+8), so:

7(3n+4)+8

We multiply parentheses

21n+28+8

We add all the numbers together, and all the variables

21n+36

Back to the equation:

-(21n+36)



We get rid of parentheses

4n-21n-36+2=0

We add all the numbers together, and all the variables

-17n-34=0

We move all terms containing n to the left, all other terms to the right

-17n=34

n=34/-17

n=-2

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