2(2m-6)+(m-7)=16

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Solution for 2(2m-6)+(m-7)=16 equation: 



2(2m-6)+(m-7)=16

We move all terms to the left:

2(2m-6)+(m-7)-(16)=0

We multiply parentheses

4m+(m-7)-12-16=0

We get rid of parentheses

4m+m-7-12-16=0

We add all the numbers together, and all the variables

5m-35=0

We move all terms containing m to the left, all other terms to the right

5m=35

m=35/5

m=7

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