2(2m+3)=4-(m-12)

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Solution for 2(2m+3)=4-(m-12) equation: 



2(2m+3)=4-(m-12)

We move all terms to the left:

2(2m+3)-(4-(m-12))=0

We multiply parentheses

4m-(4-(m-12))+6=0



We calculate terms in parentheses: -(4-(m-12)), so:

4-(m-12)

determiningTheFunctionDomain
-(m-12)+4

We get rid of parentheses

-m+12+4

We add all the numbers together, and all the variables

-1m+16

Back to the equation:

-(-1m+16)



We get rid of parentheses

4m+1m-16+6=0

We add all the numbers together, and all the variables

5m-10=0

We move all terms containing m to the left, all other terms to the right

5m=10

m=10/5

m=2

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