2(2m+24)=3(m-2)

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Solution for 2(2m+24)=3(m-2) equation: 



2(2m+24)=3(m-2)

We move all terms to the left:

2(2m+24)-(3(m-2))=0

We multiply parentheses

4m-(3(m-2))+48=0



We calculate terms in parentheses: -(3(m-2)), so:

3(m-2)

We multiply parentheses

3m-6

Back to the equation:

-(3m-6)



We get rid of parentheses

4m-3m+6+48=0

We add all the numbers together, and all the variables

m+54=0

We move all terms containing m to the left, all other terms to the right

m=-54

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