2(2m+1)=2(24-m)

Solution for 2(2m+1)=2(24-m) equation:

2(2m+1)=2(24-m)

We move all terms to the left:

2(2m+1)-(2(24-m))=0

We add all the numbers together, and all the variables

2(2m+1)-(2(-1m+24))=0

We multiply parentheses

4m-(2(-1m+24))+2=0


We calculate terms in parentheses: -(2(-1m+24)), so:

2(-1m+24)

We multiply parentheses

-2m+48

Back to the equation:

-(-2m+48)


We get rid of parentheses

4m+2m-48+2=0

We add all the numbers together, and all the variables

6m-46=0

We move all terms containing m to the left, all other terms to the right

6m=46

m=46/6

m=7+2/3