2(2m)=4(4m+2)=108

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Solution for 2(2m)=4(4m+2)=108 equation: 



2(2m)=4(4m+2)=108

We move all terms to the left:

2(2m)-(4(4m+2))=0



We calculate terms in parentheses: -(4(4m+2)), so:

4(4m+2)

We multiply parentheses

16m+8

Back to the equation:

-(16m+8)



We get rid of parentheses

22m-16m-8=0

We add all the numbers together, and all the variables

6m-8=0

We move all terms containing m to the left, all other terms to the right

6m=8

m=8/6

m=1+1/3

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