2(2m)+4(4m+2)=105

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Solution for 2(2m)+4(4m+2)=105 equation: 



2(2m)+4(4m+2)=105

We move all terms to the left:

2(2m)+4(4m+2)-(105)=0

We multiply parentheses

22m+16m+8-105=0

We add all the numbers together, and all the variables

38m-97=0

We move all terms containing m to the left, all other terms to the right

38m=97

m=97/38

m=2+21/38

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