2(2k-5)=6(k-4)+9

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Solution for 2(2k-5)=6(k-4)+9 equation: 



2(2k-5)=6(k-4)+9

We move all terms to the left:

2(2k-5)-(6(k-4)+9)=0

We multiply parentheses

4k-(6(k-4)+9)-10=0



We calculate terms in parentheses: -(6(k-4)+9), so:

6(k-4)+9

We multiply parentheses

6k-24+9

We add all the numbers together, and all the variables

6k-15

Back to the equation:

-(6k-15)



We get rid of parentheses

4k-6k+15-10=0

We add all the numbers together, and all the variables

-2k+5=0

We move all terms containing k to the left, all other terms to the right

-2k=-5

k=-5/-2

k=2+1/2

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