2(2k-3)+1=8k-11

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Solution for 2(2k-3)+1=8k-11 equation: 



2(2k-3)+1=8k-11

We move all terms to the left:

2(2k-3)+1-(8k-11)=0

We multiply parentheses

4k-(8k-11)-6+1=0

We get rid of parentheses

4k-8k+11-6+1=0

We add all the numbers together, and all the variables

-4k+6=0

We move all terms containing k to the left, all other terms to the right

-4k=-6

k=-6/-4

k=1+1/2

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