2(2k-2)=4(k-1)

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Solution for 2(2k-2)=4(k-1) equation: 



2(2k-2)=4(k-1)

We move all terms to the left:

2(2k-2)-(4(k-1))=0

We multiply parentheses

4k-(4(k-1))-4=0



We calculate terms in parentheses: -(4(k-1)), so:

4(k-1)

We multiply parentheses

4k-4

Back to the equation:

-(4k-4)



We get rid of parentheses

4k-4k+4-4=0

We add all the numbers together, and all the variables

=0

k=0/1

k=0

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