2(2k-2)=2(4K+3)

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Solution for 2(2k-2)=2(4K+3) equation: 



2(2k-2)=2(4+3)

We move all terms to the left:

2(2k-2)-(2(4+3))=0

We add all the numbers together, and all the variables

2(2k-2)-(27)=0

We add all the numbers together, and all the variables

2(2k-2)-27=0

We multiply parentheses

4k-4-27=0

We add all the numbers together, and all the variables

4k-31=0

We move all terms containing k to the left, all other terms to the right

4k=31

k=31/4

k=7+3/4

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