2(2d-4)+12=4d+2(6+2d)

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Solution for 2(2d-4)+12=4d+2(6+2d) equation: 



2(2d-4)+12=4d+2(6+2d)

We move all terms to the left:

2(2d-4)+12-(4d+2(6+2d))=0

We add all the numbers together, and all the variables

2(2d-4)-(4d+2(2d+6))+12=0

We multiply parentheses

4d-(4d+2(2d+6))-8+12=0



We calculate terms in parentheses: -(4d+2(2d+6)), so:

4d+2(2d+6)

We multiply parentheses

4d+4d+12

We add all the numbers together, and all the variables

8d+12

Back to the equation:

-(8d+12)



We add all the numbers together, and all the variables

4d-(8d+12)+4=0

We get rid of parentheses

4d-8d-12+4=0

We add all the numbers together, and all the variables

-4d-8=0

We move all terms containing d to the left, all other terms to the right

-4d=8

d=8/-4

d=-2

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